Since the base is 16, the exponent in this form is about twice as large as the equivalent in IEEE 754, in order to have similar exponent range in binary, 9 exponent bits would be required.

A minifloat in one byte (8 bit) with one sign bit, four exponent bits and three mantissa bits (in short a 1.4.3.

The signal consists of the timing variation due to the target exponent bit, and noise results from measurement inaccuracies and timing variations due to unknown exponent bits.

Seeeeeeee(1)mmmmmmmmmmmmmmmmmmmmmmm 1 Sign, 8 exponent bits, (implicit bit), 23 mantissa bits.